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Intercollegiate Math Tournament
Columbia University February 28, 2026
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ICMT consists of three rounds: the Power Round, the Constellation Round, and the Individual Round. The two divisions have separate rankings; scores in one division do not affect the other.

All answers must be submitted according to the acceptable answer formats document. Answers not submitted in the specified formats will be marked incorrect, even if mathematically equivalent. See also the common mathematical notions document for notation conventions used in the contest.

Power Round

Round Structure

Scoring

Constellation Round

The round structure and scoring are slightly different between Division A and Division B.

Division A

Round Structure

Scoring

Your team's score is the sum of the following four categories:

Base Points: Each correct answer receives 15 points. Incorrect answers receive 0 points.

Speed Bonus: Bonus points are awarded for solving problems before other teams.

Depth Bonus: Bonus points are awarded for solving multiple problems in the same constellation.

Breadth Bonus: Bonus points are awarded for solving problems in every constellation.

The maximum score on the Division A Constellation Round is $660 + 585 + 270 + 522 = \mathbf{2037}$ points.

Division B

Round Structure

Scoring

Your team's score is the sum of the following four categories:

Base Points: Each correct answer receives 15 points. Incorrect answers receive 0 points.

Speed Bonus: Bonus points are awarded for solving problems before other teams.

Depth Bonus: Bonus points are awarded for solving multiple problems in the same constellation.

Breadth Bonus: Bonus points are awarded for solving problems in every constellation.

The maximum score on the Division B Constellation Round is $570 + 495 + 225 + 435 = \mathbf{1725}$ points.

Individual Round

Round Structure

Scoring

Tiebreakers

In case of a tie, the following tiebreaker system will be used:

  1. First, the 10 short answer problems are ordered from hardest to easiest, based on the number of correct submissions.
    • The estimation problems will not be taken into account for the tiebreaker system.
    • In case of short answer problems having an equal number of solves, the problems will then be ordered from later in the test to earlier.
  2. The $n$th hardest problem is assigned a tiebreaking value of $2^{-n}$. For example, the hardest problem will have a tiebreaking value of $\frac{1}{2}$, the second hardest problem will have a tiebreaking value of $\frac{1}{4}$, et cetera.
  3. Each student's tiebreaking index is calculated as the sum of their original score and the tiebreaker values of the problems that they correctly answered.
  4. Students are ordered by their tiebreaking index, determining their tiebroken rank.

Roughly speaking, among those tied for the same score, whoever solved the hardest short answer problem is placed the highest, followed by the one who solved the next hardest, and so on.

Overall Team Score

A team's final ranking is determined entirely by their Team Score, which is the sum of the normalized scores in each round:

$$\text{Team Score} = N_{\text{Power}} + N_{\text{Constellation}} + N_{\text{Individual}}$$

Power Round

Let the team's final Power Round score be $A$, and let the tenth place score on the Power Round (for that team's respective division) be $B$. Then:

$$N_{\text{Power}} = \frac{A}{B}$$

Constellation Round

Let the team's final Constellation Round score be $A$, and let the top score on the Constellation Round (for that team's respective division) be $B$. Then:

$$N_{\text{Constellation}} = \frac{A}{B}$$

Individual Round

For each of the contestants on the team, let the contestant's Individual Round score be $A$, and let the ninetieth percentile score on the Individual Round (for that contestant's respective division) be $B$. Then the contestant has a normalized score of $\frac{A}{B}$. The team's normalized score $N_{\text{Individual}}$ is the average of all of the normalized scores of the contestants on the team. (In particular, a team's normalized individual score is not punished for the team having fewer than 4 members.)